(1) (1p) Write the function table as below. In the output column, express output B in terms of the literals $\mathrm{A}_5$ to $\mathrm{A}_0$ and constants 0 and 1 by using positional association. For instance, if the function was logical left shift (not part of the question), the output should be written as follows: $\mathrm{B}_5\mathrm{B}_4\mathrm{B}_3\mathrm{B}_2\mathrm{B}_1\mathrm{B}_0 = \mathrm{A}_4\mathrm{A}_3\mathrm{A}_2\mathrm{A}_1\mathrm{A}_00$ .
Positional association implies that $\mathrm{B}_5 = \mathrm{A}_4$ , $\mathrm{B}_4 = \mathrm{A}_3$ , $\mathrm{B}_3 = \mathrm{A}_2$ , $\mathrm{B}_2 = \mathrm{A}_1$ , $\mathrm{B}_1 = \mathrm{A}_0$ , $\mathrm{B}_0 = 0$