Förstärkarkopplingen har en icke-inverterar karaktär.

R _ {1} = 1 0 \mathrm {k} \Omega R _ {2} = 2 2 0 \mathrm {k} \Omega R _ {3} = 2 2 0 \mathrm {k} \Omega C _ {2} = 1 0 \mathrm {n F} A _ {v} = \frac {Z _ {1} + Z _ {2}}{Z _ {1}}, \quad Z _ {1} = R _ {1}, \quad Z _ {2} = \left(R _ {3} + \frac {1}{j \omega c}\right) / / R _ {2} = \frac {R _ {2} (1 + j \omega R _ {3} C)}{1 + j \omega \left(R _ {2} + R _ {3}\right) C} A _ {v} = \frac {Z _ {1} + Z _ {2}}{Z _ {1}} = \frac {R _ {1} (1 + j \omega (R _ {2} + R _ {3}) C) + R _ {2} (1 + j \omega R _ {3} C)}{R _ {1} (1 + j \omega (R _ {2} + R _ {3}) C)} A _ {v} = \frac {R _ {1} + R _ {2} + j \omega (R _ {2} R _ {3} + (R _ {2} + R _ {3}) R _ {1}) C}{R _ {1} (1 + j \omega (R _ {2} + R _ {3}) C)} A _ {v} = \frac {R _ {1} + R _ {2}}{R _ {1}} \cdot \frac {1}{1 + j \omega (R _ {2} + R _ {3}) C} \cdot (1 + j \omega \frac {R _ {2} R _ {3} + (R _ {2} + R _ {3}) R _ {1}}{R _ {1} + R _ {2}} C) A _ {v} = \frac {R _ {1} + R _ {2}}{R _ {1}} \cdot \frac {1 + j \omega (R _ {3} + R _ {1} / / R _ {2}) C}{1 + j \omega (R _ {2} + R _ {3}) C} \Rightarrow f _ {1} = \frac {1}{2 \pi (R _ {2} + R _ {3}) C} = 36,2 \text{ Hz}, f _ {2} = \frac {1}{2 \pi (R _ {3} + R _ {1} / / R _ {2}) C} = 69,3 \text{ Hz}

Om kondensator inte leder (låga f), dvs. avbrott: $\frac{R_1 + R_2}{R_1} = 23\, \text{ggr} = 27\, \text{dB}$
För höga frekvenser leder kondensator: $\frac{R_1 + R_2}{R_3} = 12\, \text{ggr} = 21,6\, \text{dB}$