Consider the circuit shown in Fig. 5, where the BJT has the following characteristics: $V_{BE}=0.6\,V$ , $V_{CE,sat}=0.2\,V$ , $\beta=h_{FE}=150$ .
Suppose that the OpAmp is not ideal, having the following characteristics: $R_{in}=1\,M\Omega$ (across the inverting and non-inverting terminals), $R_{out}=50\,\Omega$ , open-loop gain $A_{o}=10^{9}$ , and supply voltages of $\pm 15\,V$ .
Let the supply voltage be $V_{S}=12\,V$ , and that the resistor in the figure have resistance of $R=1\,\Omega$ .
For $V_{in}(t)=5\,V$ (constant value), determine the output voltage $V_{out}(t)$ , the base current $I_{B}$ and the operation region of the BJT.
Note: for a few points deduction, you can solve the question assuming an ideal OpAmp.

Figure 5: Circuit for Question B.3.